Euler #1

Yosh, tantangan euler #1 (https://projecteuler.net/archives)

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

#include
using namespace std;
int main ()
{
int sum=0,b;
cout<<"Masukan Sebuah Bilangan : " ; cin>>b ;
for (int a=1;a<b;a++)
{
if (a %3 == 0 || a %5 == 0)
sum += a;
}
cout<<sum<<endl;

system ("pause");
return 0;
}
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